x^2+6x=10800

Solution for x^2+6x=10800 equation:

x^2+6x=10800

We move all terms to the left:

x^2+6x-(10800)=0

a = 1; b = 6; c = -10800;
Δ = b2-4ac
Δ = 62-4·1·(-10800)
Δ = 43236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{43236}=\sqrt{36*1201}=\sqrt{36}*\sqrt{1201}=6\sqrt{1201}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{1201}}{2*1}=\frac{-6-6\sqrt{1201}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{1201}}{2*1}=\frac{-6+6\sqrt{1201}}{2}
$